C语言两个整型数的算术运算?答:int main(void){ int a,b;//a和b是输入的两个整型值 int add,sub,mul,div,oct;//分别存放和,差,积,商,余数 scanf("%d",&a);//输入a scanf("%d",&b);//输入b add=a+b;//和 sub=a-b;//差 mul=a*b;//积 div=a/b;//商 oct=a%b;//余数 printf("和=%d\n",add);...
输入两个int型数a,b,求a/b的商,不必考虑b为0的情况,输出c,保留两位小数...答:using namespace std;int main() { int a, b;float c;scanf("%d%d", &a, &b);c = a * 1.00 / b;printf("%.2f", c);return 0;} C include <stdio.h> int main() { int a, b;float c;scanf("%d%d", &a, &b);c = a * 1.00 / b;printf("%.2f", c);return...