高中数学题答:8. 据题意,梁的强度y=kbh^2,b∈(0,d),k是正的常数.现b^2+h^2=d^2,将h^2=d^2−b^2代入得y=kb(d^2−b^2).现y'=kd^2−3kb^2.令y'=0,解得(0,d)内的唯一驻点b0=根号3/3d,且y'(b0)=−6kb0<0,b0是极大值点,也是最大值点.因此,当断面底...
高中数学题答:参考计算表:n = 0 s = 0 A = Table[{i, "--"}, {i, 256}]While[s < 6, n = n + 1; s = s + 1/n; A[[n]][[2]] = N[s, 6]]Print[A]{{1,1.00000},{2,1.50000},{3,1.83333},{4,2.08333},{5,2.28333},{6,2.45000},{7,2.59286},{8,2.71786}...