输入今天的日期y(年)、m(月)、日(d),输入明天的日期。编写程序答:include <stdio.h>int main(){int year,month,day;int maxdays[]={31,28,31,30,31,30,31,31,30,31,30,31};printf("请输入年月日,中间用空格隔开!\n");scanf("%d %d %d",&year,&month,&day);if(year%400==0 || (year%4==0 && year%100!=0)) maxdays[1]=29;//闰年...