第1个回答 2015-05-06
解答第1题:
ΣMA =0, FBy.4m -(2KN/m).4m.2m =0
FBy =4KN(向上)
ΣFy =0, FAy +FBy =0
FAy +4KN =0,
FAy = -4KN(向下)
ΣFx =0, FAx +(2KN/m).4m =0
FAx = -8KN(向左)
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解答第2题:
ΣMA =0, FBy.4m -20KN.2m -(2KN/m).2m.1m =0
FBy =11KN(向上)
ΣFy =0, FAy +FBy -20KN -(2KN/m).2m.=0
将FBy =11KN代入上式得:FAy =13KN(向上)
ΣFx =0, FAx =0本回答被网友采纳