arcsin(y/x)=√(x²-y²)
==> 1/√[1-(y/x)²]×(y/x)'=(1/2)·[1/√(x²-y²)]×(x²-y²)'
==> [x/√(x²-y²)]×[(y'*x-y)/x²]=(1/2)·[1/√(x²-y²)]×(2x-2yy')
==> y'*x-y=x(x-2yy')=x²-2xyy'
==> (x+2xy)y'=x²+y
==> y'=(x²+y)/(x+2xy)
追问求微分
追答所以,dy=[(x²+y)/(x+2xy)]dx
追问后来想明白了 x^2从根号里开出来时候要带绝对值 因为开不出负的 所以导数是(|x|y+x^3)/x^2 y+x|x|
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