第1个回答 2019-06-12
假设螃蟹x蝴蝶y螳螂z
则:x
+
y
+
z
=
18
8x
+
6y
+
6z
=
118
2y
+
z
=
20
用消元法解得:x
=
5
,y
=
7
,z
=
6
假设x天有雨,则:
12x
+
20·[(112/14)
-
x]
=
112
,解得x
=
6
假设公猴x
,则母猴x
+
4
,猴崽
=
38
-
x-(x
+
4)
=
34
-
2x
则:10x
+
8(x
+
4)
+
5(34
-
2x)
=
266
,解得x
=
8
∴公猴8母猴12猴崽18