有没有数学达人帮我解答一下这张卷子？100分悬赏

Question

如题所述

Answer 1

一、
1、1
2、tanα
3、sinα
4、cosα
5、-tanα
6、T=2π
7、(0,1)、(π/2,0)、(π,-1)、(3π/2,0)、(2π,1)
二、
1、tanα=5
(3sinα-4cosα)/(2sinα-3cosα)
=(3tanα-4)/(2tanα-3)
=(3×5-4)/(2×5-3)
=11/7
2、看不见题目
3、tan(-7π/4)
=tan(2π-π/4)
=tan(-π/4)
=-tanπ/4
=-1
三、
1、(1+cosα)(1-cosα)
=1-(cosα)^2
=(sinα)^2
2、[sin(2π+α)tan(π+α)tan(π-α)]/[cos(π+α)tan(3π-α)]
=[sinαtanα(-tanα)]/[(-cosα)tan(-α)]
=(sinα/cosα)(tanα)^2/(-tanα)
=-(tanα)^2

Answer 2

书

Answer 3