ãå·²ç¥ãNaOHï¼m = 4.0 g ï¼ M= 40.0 g/mol ï¼
溶åï¼æ°´ï¼m= 100 gï¼æº¶æ¶²ä½ç§¯væç
§100ml
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1) NaOHè´¨éåæ°w = 4.0/104 = 3.85%;
2) è´¨éæµåº¦Ï = m/v = 4.0/100 = 40 mg/ml
3) ç©è´¨çéæµåº¦c = ï¼m/ Mï¼/ v= ï¼4.0/40.0ï¼/0.100 = 1.0 mol/L
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