如题所述
请问基础解系怎么算的啊?
,(a):x1+x2=0; x2-x4=0秩为2,自由变量x3,x4. ﹙x3,x4﹚=﹙1,0﹚得到(x1,x2,x3,x4﹚'=﹙0,0,1,0﹚′ ﹙x3,x4﹚=﹙1,1﹚,得到(x1,x2,x3,x4﹚'=﹙1,-1,0,1﹚′