第1个回答 2011-09-17
N:=60;
K值:="KDJ.K";
DD:=C=LLV(C,N);
DDSJ:=BARSLAST(REF(DD,1));
DDGJ:=REF(CLOSE,DDSJ+1)>CLOSE;
KDZB:=REF(K值,DDSJ+1)<K值;
K底背离:=DDGJ AND KDZB;
GD:=C=HHV(C,N);
GDSJ:=BARSLAST(REF(GD,1));
GDGJ:=REF(CLOSE,GDSJ+1)<CLOSE;
KGZB:=REF(K值,GDSJ+1)>K值;
K顶背离:=GDGJ AND KGZB;
MACD:="MACD.MACD";
MDZB:=REF(MACD,DDSJ+1)<MACD;
M底背离:=DDGJ AND MDZB;
MGZB:=REF(MACD,GDSJ+1)>MACD;
M顶背离:=GDGJ AND MGZB;
RSI:="RSI.RSI1";
RDZB:=REF(RSI,DDSJ+1)<RSI;
R底背离:=DDGJ AND RDZB;
RGZB:=REF(RSI,GDSJ+1)>RSI;
R顶背离:=GDGJ AND RGZB;
TYP:=(HIGH + LOW + CLOSE)/3;
CCI:=(TYP-MA(TYP,N))/(0.015*AVEDEV(TYP,N));
CDZB:=REF(CCI,DDSJ+1)<CCI;
C底背离:=DDGJ AND CDZB;
CGZB:=REF(CCI,GDSJ+1)>CCI;
C顶背离:=GDGJ AND CGZB;
DRAWTEXT(K顶背离,IF(BARSCOUNT(C),27.5,29),'(×)'),LINETHICK2,COLORRED;
DRAWTEXT(M顶背离,IF(BARSCOUNT(C),24.5,26),'(×)'),LINETHICK2,COLORMAGENTA;
DRAWTEXT(R顶背离,IF(BARSCOUNT(C),20.5,22.1),'(×)'),LINETHICK2,COLORBLUE;
DRAWTEXT(C顶背离,IF(BARSCOUNT(C),16.6,18.1),'(×)'),LINETHICK2,COLORGREEN;
DRAWTEXT(C底背离,IF(BARSCOUNT(C),12,14.2),'(√)'),LINETHICK2,COLORGREEN;
DRAWTEXT(R底背离,IF(BARSCOUNT(C),8.5,10),'(√)'),LINETHICK2,COLORBLUE;
DRAWTEXT(M底背离,IF(BARSCOUNT(C),4.5,6),'(√)'),LINETHICK2,COLORMAGENTA;
DRAWTEXT(K底背离,IF(BARSCOUNT(C),1.5,3),'(√)'),LINETHICK2,COLORRED;本回答被提问者采纳