设æ°é½æ¬¡æ¹ç¨ç»çæ ¹ä¸ºx=c1 s1 + c2 s2 + c3s3=(c1+2c2, c2+2c3,c1+c3,c1-c2-c3)', s1,s2,s3为åé½æ¬¡æ¹ç¨ç»çåºç¡è§£ç³»ï¼c1,c2,c3为任æ常æ°
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3c1+2c2+2c3 =0
5c1 + 2c2 +2c3 =0
=> c1=0, c2+c3=0
æ以æ°æ¹ç¨ç»çåºç¡è§£ç³»æ¯s2-s3
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