(1)点(n,Sn/n)在直线y=3x-2上,
∴Sn/n=3n-2,
∴Sn=3n^2-2n,①
n=1时a1=1,
n>1时S<n-1>=3(n-1)^2-2(n-1),②
①-②,an=3(2n-2)-2=6n-5,
n=1时上式也成立,∴an=6n-5.
(2)bn=3/(an*a<n+1>)=(1/2)[1/(6n-5)-1/(6n+1)],
∴Tn=(1/2)[1-1/7+1/7-1/13+……+1/(6n-5)-1/(6n+1)]
=(1/2)[1-1/(6n+1)]
=3n/(6n+1)<m/20,
∴m>60n/(6n+1)=10-6/(6n+1)对n∈N+恒成立,
∴m>=10.
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