导函数图像对称轴

Question

如题所述

Answer 1

解f'(x)=[-sin(2x-π/3)+4]'
=(-sin(2x-π/3))'+4'
=-(sin(2x-π/3))'
=-cos(2x-π/3)(2x-π/3)'
=-2cos(2x-π/3)
令2x-π/3=kπ，k属于Z
解得x=kπ/2+π/6,k属于Z
故函数的对称轴为x=kπ/2+π/6,k属于Z。