设{An}是等差数列,其前n项和为Sn.求证数列{Sn除以n}为等差数列

如题所述

Sn=(a1+a2+a3+..+an)
=na1+n(n-1)d/2

Sn/n=a1+(n-1)d/2;
Sn-1/n-1=a1+(n-2)d/2
Sn/n- Sn-1/n-1=d/2为一常数,故{Sn除以n}为等差数列
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